AR003IAW
2-Methyl-4,5-dihydro-1H-imidazole
Manufacturer: Aaron Chemicals LLC
CAS Number: 534-26-9
Select a Size
| Pack Size | SKU | Availability | Price |
|---|---|---|---|
| 1g | AR003IAW-1g | In Stock | ₹ 1,368.96 |
| 5g | AR003IAW-5g | In Stock | ₹ 5,646.96 |
| 25g | AR003IAW-25g | In Stock | ₹ 24,812.40 |
AR003IAW - 1g
In Stock
Quantity
1
Base Price: ₹ 1,368.96
GST (18%): ₹ 246.413
Total Price: ₹ 1,615.373
Mdl Number
MFCD00051490
Molecular Formula
C4H8N2
Molecular Weight
84.1197
Chemical Name
2-Methyl-4,5-dihydro-1H-imidazole
Smiles
CC1=NCCN1
Other Options
| Image | Product Name | Manufacturer | Price Range | |
|---|---|---|---|---|
 | 2-Methyl-4,5-dihydro-1h-imidazole | ChemScene | ₹ 8,128.20 - ₹ 89,495.76 | |
 | 534-26-9 | 2-Methyl-2-imidazoline | A2B Chem | ₹ 1,112.28 - ₹ 25,668.00 |
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Mdl Number: MFCD00051490
Molecular Formula: C4H8N2
Molecular Weight: 84.1197
Chemical Name: 2-Methyl-4,5-dihydro-1H-imidazole
Smiles: CC1=NCCN1
Mdl Number:
MFCD00051490
Molecular Formula:
C4H8N2
Molecular Weight:
84.1197
Chemical Name:
2-Methyl-4,5-dihydro-1H-imidazole
Smiles:
CC1=NCCN1
Mdl Number: MFCD01631541
Molecular Formula: C8H8F3NO
Molecular Weight: 191.1504
Chemical Name: 2-Methyl-4-(trifluoromethoxy)aniline
Smiles: Nc1ccc(cc1C)OC(F)(F)F
Mdl Number:
MFCD01631541
Molecular Formula:
C8H8F3NO
Molecular Weight:
191.1504
Chemical Name:
2-Methyl-4-(trifluoromethoxy)aniline
Smiles:
Nc1ccc(cc1C)OC(F)(F)F
Mdl Number: MFCD00190640
Molecular Formula: C5H7F3O2
Molecular Weight: 156.1030896
Chemical Name: 2-METHYL-4,4,4-TRIFLUOROBUTYRIC ACID
Smiles: CC(C(=O)O)CC(F)(F)F
Mdl Number:
MFCD00190640
Molecular Formula:
C5H7F3O2
Molecular Weight:
156.1030896
Chemical Name:
2-METHYL-4,4,4-TRIFLUOROBUTYRIC ACID
Smiles:
CC(C(=O)O)CC(F)(F)F
Mdl Number: MFCD00025648
Molecular Formula: C15H17N3
Molecular Weight: 239.3156
Chemical Name: 2-Methyl-4-dimethylaminoazobenzene
Smiles: Cc1ccccc1/N=N/c1ccc(cc1)N(C)C
Mdl Number:
MFCD00025648
Molecular Formula:
C15H17N3
Molecular Weight:
239.3156
Chemical Name:
2-Methyl-4-dimethylaminoazobenzene
Smiles:
Cc1ccccc1/N=N/c1ccc(cc1)N(C)C