BA16209

1427504-03-7 | Methyl 4-fluoro-1H-indazole-3-carboxylate

Manufacturer: A2B Chem

CAS Number: 1427504-03-7

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Pack Size SKU Availability Price
100mg BA16209-100mg In Stock ₹ 10,352.76
250mg BA16209-250mg In Stock ₹ 17,112.00

BA16209 - 100mg

₹ 10,352.76

In Stock

Quantity

1

Base Price: ₹ 10,352.76

GST (18%): ₹ 1,863.497

Total Price: ₹ 12,216.257

Catalog Number

BA16209

Chemical Name

Methyl 4-fluoro-1H-indazole-3-carboxylate

Cas Number

1427504-03-7

Molecular Formula

C9H7FN2O2

Molecular Weight

194.1625

Mdl Number

MFCD23703856

Smiles

COC(=O)c1n[nH]c2c1c(F)ccc2

Other Options

Image Product Name Manufacturer Price Range
50-247-2391
eMolecules​ AstaTech / METHYL 4-FLUORO-1H-INDAZOLE-3-CARBOXYLATE / 0.1g / 718059353 / E83266 / 95.000 / 1427504-03-7 / MFCD23703856 / 194.165 / C9H7FN2O2
eMolecules​ ₹ 22,544.20
CS-0571842
Methyl 4-fluoro-1H-indazole-3-carboxylate
ChemScene ₹ 20,106.60 - ₹ 90,864.72

Compare Similar Items

Show Difference

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A2B Chem

BA16209

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Catalog Number:
BA16209

Chemical Name:
Methyl 4-fluoro-1H-indazole-3-carboxylate

Cas Number:
1427504-03-7

Molecular Formula:
C9H7FN2O2

Molecular Weight:
194.1625

Mdl Number:
MFCD23703856

Smiles:
COC(=O)c1n[nH]c2c1c(F)ccc2

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A2B Chem

BA16258

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Catalog Number:
BA16258

Chemical Name:
12,13-Bis(2-butyloctyl)-12,13-dihydro-3,9-diundecyl-dithieno[2'',3'':4',5']thieno[2',3':4,5]pyrrolo[3,2-e:2',3'-g][2,1,3]benzothiadiazole

Cas Number:
2376334-93-7

Molecular Formula:
C64H98N4S5

Molecular Weight:
1083.8147

Mdl Number:
__

Smiles:
CCCCCCC(Cn1c2c(c3c1c1c(c4c3nsn4)c3c(n1CC(CCCCCC)CCCC)c1c(s3)c(cs1)CCCCCCCCCCC)sc1c2scc1CCCCCCCCCCC)CCCC

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A2B Chem

BA16259

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Catalog Number:
BA16259

Chemical Name:
2,5-Diacetylfuran

Cas Number:
38071-72-6

Molecular Formula:
C8H8O3

Molecular Weight:
152.1473

Mdl Number:
__

Smiles:
CC(=O)c1ccc(o1)C(=O)C

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A2B Chem

BA16260

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Catalog Number:
BA16260

Chemical Name:
4-[(3-Methyl-2-buten-1-yl)oxy]benzenemethanol

Cas Number:
34593-47-0

Molecular Formula:
C12H16O2

Molecular Weight:
192.2542

Mdl Number:
__

Smiles:
OCc1ccc(cc1)OC/C=C(\C)/C