BL20854

1261849-95-9 | 3-Chloro-5-(difluoromethoxy)aniline

Manufacturer: A2B Chem

CAS Number: 1261849-95-9

Select a Size

Pack Size SKU Availability Price
50mg BL20854-50mg In Stock ₹ 16,085.28
100mg BL20854-100mg In Stock ₹ 29,004.84

BL20854 - 50mg

₹ 16,085.28

In Stock

Quantity

1

Base Price: ₹ 16,085.28

GST (18%): ₹ 2,895.35

Total Price: ₹ 18,980.63

Catalog Number

BL20854

Chemical Name

3-Chloro-5-(difluoromethoxy)aniline

Cas Number

1261849-95-9

Molecular Formula

C7H6ClF2NO

Molecular Weight

193.5784

Mdl Number

MFCD18392560

Smiles

FC(Oc1cc(N)cc(c1)Cl)F

Other Options

Image Product Name Manufacturer Price Range
CS-0310919
3-Chloro-5-(difluoromethoxy)aniline
ChemScene ₹ 13,946.28 - ₹ 55,271.76

Related Products

Img

A2B Chem

BD06345

--

Img

A2B Chem

BC82483

--

Img

A2B Chem

BH71214

--

Img

A2B Chem

BB96033

--

Img

A2B Chem

BB93010

--

Img

A2B Chem

AX09578

--

Img

A2B Chem

BB93071

--

Img

A2B Chem

BC88391

--

Compare Similar Items

Show Difference

Img

A2B Chem

BL20854

--


Catalog Number:
BL20854

Chemical Name:
3-Chloro-5-(difluoromethoxy)aniline

Cas Number:
1261849-95-9

Molecular Formula:
C7H6ClF2NO

Molecular Weight:
193.5784

Mdl Number:
MFCD18392560

Smiles:
FC(Oc1cc(N)cc(c1)Cl)F

Img

A2B Chem

BL20855

--


Catalog Number:
BL20855

Chemical Name:
Potassium (E)-(2-cyclohexylvinyl)trifluoroborate

Cas Number:
1005201-61-5

Molecular Formula:
__

Molecular Weight:
__

Mdl Number:
MFCD03844605

Smiles:
__

Img

A2B Chem

BL20856

--


Catalog Number:
BL20856

Chemical Name:
5-Chloro-N1-(dibenzo[b,d]furan-4-yl)-N3-(dibenzo[b,d]thiophen-2-yl)-N1,N3-diphenylbenzene-1,3-diamine

Cas Number:
2845127-75-3

Molecular Formula:
__

Molecular Weight:
__

Mdl Number:
__

Smiles:
__

Img

A2B Chem

BL20857

--


Catalog Number:
BL20857

Chemical Name:
(E)-1-Methyl-4-(4-(methyl(2-(stearoyloxy)ethyl)amino)styryl)pyridin-1-ium

Cas Number:
2075674-45-0

Molecular Formula:
C35H55N2O2

Molecular Weight:
535.8234

Mdl Number:
__

Smiles:
CCCCCCCCCCCCCCCCCC(=O)OCCN(c1ccc(cc1)C=Cc1cc[n+](cc1)C)C